You know what your completely right. The block only will take what the
yield method returns to it. So apparently when instantiating an array
with that first argument setting a size limit for array, the
constructor contains a yield method which yields each iteration of
that size limit. And then the return value is passed back to the
resutlt of the yield and that value is then idnexed into the array
until the size limit has been reached.

On Feb 25, 3:15 pm, Valery Kvon <[email protected]> wrote:
> On 26.02.2012, at 0:07, John Merlino wrote:
>
> > thanks for response but that was just an example and not really what
> > my question was about.
>
> > Perhaps this is a better example:
>
> >>> Array.new(10) do |id|
> > ?>   "'#{(id + 1).to_s.rjust(2,"0")}'"
> >>> end
> > => ["'01'", "'02'", "'03'", "'04'", "'05'", "'06'", "'07'", "'08'",
> > "'09'", "'10'"]
>
> > Why is "id" not the array instance. It obviously is an integer.
> > Otherwise this would have failed with (id +1).
>
> I don't understand Why are you expecting an Array??
>
> new(size=0, obj=nil)click to toggle source
> new(array)
> new(size) {|index| block }
> Returns a new array. In the first form, the new array is empty. In the second 
> it is created with sizecopies of obj (that is, size references to the same 
> obj). The third form creates a copy of the array passed as a parameter (the 
> array is generated by calling to_ary on the parameter). In the last form, an 
> array of the given size is created. Each element in this array is calculated 
> by passing the element’s index to the given block and storing the return 
> value.
>
> There must be code inside like that:
>
> if block_given?
>   yield index
> end

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