Write a loop that generates the desired indexes and then reference arr:
(0..5).each do |j|
i = 10*j
puts "#{arr[i]} at #{i}"
end
Your example output does not match the code. It does not include 0, 20,
and 40.
On Thursday, May 23, 2013 5:24:36 AM UTC-4, Ruby-Forum.com User wrote:
>
> Can anyone help me on how to skip index in ARRAY.each_with_index loop?
>
> Please look at below case:
>
> In a ARRAY.each_with_index loop, I would like increase the index by 10
> whenever a condition is met.
>
> arr is array of numbers from 0 to 50
> arr.each_with_index do |x,i|
> if i % 10 == 0
> puts "#{x} at #{i}"
> i = i+10 //index increased by 10
> end
> end
>
> The output should be:
> 10 at 10
> 30 at 30
> 50 at 50
>
> Thanks
> Ajit
>
> --
> Posted via http://www.ruby-forum.com/.
>
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