I don't think that will be possible.
A variable has an identifier ( in your case, n1 ) and a reference to an
object ( Sample:0x13bc648 ) so when you say "n1" , it knows which object it
references and returns that. As far as I know Ruby doesn't keep track of
reference counts of an object and the object has no way of finding out
which variable references itself.
But one inefficient way to achieve what you want would be to iterate
through all the local variables and print the names of all local variables
that has a particular object ID.
a = b = "hello world"
local_variables.each {|x| puts x if (eval x.to_s).object_id == a.object_id}
On 6 September 2013 13:07, Love U Ruby <[email protected]> wrote:
> Follow the code :-
>
>
> class Sample
> def bar
> p method(__method__).receiver # only `self` would do the trick.
> end
> end
>
> n1=Sample.new # => #<Sample:0x13bc648>
> n2=Sample.new # => #<Sample:0x13bc630>
>
> n1.bar # => #<Sample:0x13bc648>
> n2.bar # => #<Sample:0x13bc630>
>
> But this is my try. I am looking for any method is available in
> Ruby,into which say if I pas n1.object_id or #<Sample:0x13bc648>,I will
> get back in return the local variable name say here it is - n1 ?
>
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