> On 2015-Dec-16, at 17:24 , Scott Eisenberg <[email protected]> wrote:
>
> Looks to me like you will have an Array of hashes.
>
> The ruby way something like a single line array select
>
> t.select{|tt| a.between?(tt[:min], tt[:max]) && b.between?(tt[:b_min],
> tt[:b_max])}
>
> create the array initially with something like
>
> t = Array.new
> t << {a_min: 1, a_max:10, b_min: 100, b_max: 1000, p1: 1, p2: 2, p3: 3}
> t << {a_min: 1, a_max:10, b_min: 100, b_max: 1000, p1: 1, p2: 2, p3: 3}
>
> (fill in your data)
>
> you could do t = [{your data}, {your hash data}….]
>
> If you only want the first value in the array that matches, use t.detect
> rather than t.select
>
> It will return either any array of matching hashes or with detect the first
> one…
>
>
> Use the rails console to test all this stuff. rails c
>
Or, use the fact that you have a well-defined range for the 'a' and 'b'
TABLE = [
{a: 40.000..47.95, b: -95.0..-74.01, p1: 12.8, p2: 6.5, p3: 177.82, p4:
0.9150, p5: 68.62, p6: 0.9020},
{a: 42.000..47.95, b: -68.0..-59.50, p1: 11.0, p2: 5.8, p3: 185.20, p4:
0.9377, p5: -11.80, p6: 0.9538},
{a: 44.000..47.95, b: -74.2..-68.05, p1: 12.8, p2: 6.5, p3: 157.45, p4:
0.9194, p5: 37.55, p6: 0.9297},
{a: 46.000..66.00, b: -59.5..-51.00, p1: 8.8, p2: 3.7, p3: 164.96, p4:
0.9465, p5: -207.54, p6: 1.0342},
{a: 47.951..66.00, b: -79.0..-59.55, p1: 12.8, p2: 6.5, p3: 157.45, p4:
0.9194, p5: 37.55, p6: 0.9297},
{a: 47.951..66.00, b: -95.0..-79.01, p1: 12.8, p2: 6.5, p3: 177.82, p4:
0.9150, p5: 68.62, p6: 0.9020},
];
def params(a:, b:)
TABLE.detect {|h| h[:a].cover?(a) && h[:b].cover?(b) }
end
irb2.2.3> params(a: 45.2, b: -70)
#2.2.3 => {:a=>44.0..47.95, :b=>-74.2..-68.05, :p1=>12.8, :p2=>6.5,
:p3=>157.45, :p4=>0.9194, :p5=>37.55, :p6=>0.9297}
Obviously build your table as big as you need, but you might have to think
about a more suitable data structure if this crude linear search through an
array isn't fast enough.
-Rob
>
>
>> On Dec 16, 2015, at 3:55 PM, Suo Huang <[email protected]
>> <mailto:[email protected]>> wrote:
>>
>> Hi all,
>>
>> I am a newbie in Ruby, and I am having a small question with the hash table.
>> If anyone could give me some suggestions that would be great!
>>
>> Considering creating a hash table like this:
>>
>> a_Min a_Max b_Min b_Max p1 p2 p3
>> p4 p5 p6
>> 40.000 47.95 -95.0 -74.01 12.8 6.5 177.82
>> 0.9150 68.62 0.9020
>> 42.000 47.95 -68.0 -59.50 11.0 5.8 185.20
>> 0.9377 -11.80 0.9538
>> 44.000 47.95 -74.2 -68.05 12.8 6.5 157.45
>> 0.9194 37.55 0.9297
>> 46.000 66.00 -59.5 -51.00 8.8 3.7 164.96
>> 0.9465 -207.54 1.0342
>> 47.951 66.00 -79.0 -59.55 12.8 6.5 157.45
>> 0.9194 37.55 0.9297
>> 47.951 66.00 -95.0 -79.01 12.8 6.5 177.82
>> 0.9150 68.62 0.9020
>> ...
>>
>> If giving any (a,b), it will fall within the four boundary control values in
>> the hash table (a_Min, a_Max, b_min, b_Max) and returns its relative
>> parameters (p1, p2, p3....)
>>
>> I am trying something like this:
>>
>> def functionXXX(a, b)
>> threshold = XXX # how to create a
>> hash table with the above data?
>> for t in threshold do
>> if (t[:a_Min]<=a && a<t[:a_Max] && t[:b_Min]<=b && b<t[:b_Max])
>> then #if there is a smarter way in Ruby for this?
>> return t
>> break
>> end
>> end
>> end
>>
>> Would this be the correct way of doing this task in Ruby?
>>
>> Thanks!
>>
>> Suo
>>
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