string = '10.0'
string.sub!(/\.\d+/, '')
This will replace in place (sub!) any dot (\.) followed by at least
one number (\d+) with nothing ('').
Pepe
On Feb 27, 4:37 pm, northband_101 <[email protected]> wrote:
> Awesome - this is a start - I'll take it from here.
>
> Thanks!
>
> On Feb 27, 4:14 pm, Rob Biedenharn <[email protected]>
> wrote:
>
> > On Feb 27, 2009, at 2:47 PM, northband wrote:
>
> > > Hi -
>
> > > I would like to use gsub() to strip decimals with trailing zeros from
> > > a string. My string looks like this:
> > > --
> > > 19.0 " / 482.600 mm
> > > --
>
> > > I would like to end up with this:
> > > --
> > > 19 " / 482.6 mm
> > > --
>
> > > Anyone have a regular expression that can do this?
>
> > > Thanks!
>
> > It depends on how you make the string.
>
> > "19.0".sub(/\.?0+\z/,'') #=> "19"
> > "482.600".sub(/\.?0+\z/,'') #=> "482.6"
>
> > If you replace \z with (\D|\z) and substitute '\1', it might work.
> > (You can try it out yourself.)
>
> > -Rob
>
> > Rob Biedenharn http://agileconsultingllc.com
> > [email protected]
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