Sure i did using gsub operator and then i again opened using hpricot like
this
doc = Hpricot(open('Delhi.txt'))
x=doc.to_s
doc1=x.gsub(/<(\/?)li><span>/,'</li></see><see><span>')
doc2=Hpricot(doc1.to_s)
doc2.search('li').each do |z|
puts z.inner_text
end
On Thu, Sep 10, 2009 at 12:48 PM, Abhinav Saxena <[email protected]>wrote:
>
> Can you let us know how you did it using Hpricot?
>
> --
> अभिनव
> http://twitter.com/abhinav
>
>
>
>
> On Thu, Sep 10, 2009 at 12:41 PM, prashanth hiremath
> <[email protected]> wrote:
> > Thax for reply i did using hpricot
> >
> >
> > On Thu, Sep 10, 2009 at 12:33 PM, Abhinav Saxena <[email protected]>
> > wrote:
> >>
> >> I don't know Hpricot, but what you can do is: first open the file and
> >> do a gsub on the content, save it in a different/same file, and then
> >> open it using Hpricot. Just to warn you, won't be very efficient if
> >> files are huge or there are lot many files you want to process.
> >>
> >> I think, there must be some more simpler way of doing it as well.
> >>
> >> Thanks,
> >> Abhinav
> >> --
> >> अभिनव
> >> http://twitter.com/abhinav
> >>
> >>
> >>
> >>
> >> On Thu, Sep 10, 2009 at 10:25 AM, prashanth hiremath
> >> <[email protected]> wrote:
> >> > Thank u i have done different method m using gsub operator i replaces
> >> > the
> >> > tags to the form ,but problem is that
> >> >
> >> > if
> >> > doc = Hpricot(open('Delhi.txt'))
> >> > x=doc.to_s
> >> > doc1=x.gsub(/<(\/?)li><span>/,
> >> > '</li></see><see><span>')
> >> >
> >> > puts doc1
> >> > doc1.search('span').each do |y|
> >> > puts y.inner_text
> >> > end
> >> >
> >> >
> >> > its giving error
> >> >
> >> > undefined method `search' for #<String:0xb7d0bc74> (NoMethodError)
> >> > because doc1 is string how can i conevrt so that i can read the file
> >> > again
> >> > by hpricot
> >> >
> >> > On Wed, Sep 9, 2009 at 6:42 PM, Frederick Cheung
> >> > <[email protected]> wrote:
> >> >>
> >> >>
> >> >>
> >> >> On Sep 9, 12:50 pm, prashanth hiremath <[email protected]
> >
> >> >> wrote:
> >> >> > Hi
> >> >> >
> >> >> > Please help me i want to replace the tag
> >> >> >
> >> >> > </li><span> to </li></see><see><span> at time
> >> >> >
> >> >> > can anybody in world give me an solution
> >> >> >
> >> >>
> >> >> A little more context would be helpful.
> >> >>
> >> >> Fred
> >> >> > Regards
> >> >> >
> >> >> > Prashant
> >> >>
> >> >
> >> >
> >> > >
> >> >
> >>
> >>
> >
> >
> > >
> >
>
> >
>
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups "Ruby
on Rails: Talk" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/rubyonrails-talk?hl=en
-~----------~----~----~----~------~----~------~--~---
