Thanks!

I did it that way Aldric. It seems to be the better way. I will have a
lots of rows in the database, so I wanted to boost the performance.
That's why I want only to retrieve the specific day.

Thanks again! :D

On 21 sep, 21:29, Aldric Giacomoni <[email protected]>
wrote:
> It depends how it' stored in the Database.
> If it is stored in a string of format 'MM/DD', then I'd probably do
> something like this:
>
> def find_birthdays
>   mmdd = Date.today.to_s.gsub('-', '/')[5..9]
>   @birthdays = Birthday.find :all, :conditions => ['b_date like ?',
> mmdd]
> end
>
> Just make sure the month and day are always two digits.
> And there might be a smarter way to do it than using gsub, but I don't
> know it off-hand.
> --
> Posted viahttp://www.ruby-forum.com/.
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