yea, I have been using reg exp and ruby for years. and this is a puzzle. On Mar 1, 10:00 am, Philip Hallstrom <[email protected]> wrote: > On Mar 1, 2010, at 9:50 AM, [email protected] wrote: > > > > > > > I am trying to split some text into an array seperated by one or more > > <br> > > > Here is some test code: > > > s = "one<br>two<br><br>three<br><br><br>four" > > p s.split(/(<br>)+/); > > > it should split into ["one","two","three","four"] because the / > > (<br>)+/ pattern should use one or more <br> as the pattern to split > > around > > > but it does this > > ["one", "<br>", "two", "<br>", "three"] > > > Why does it do this and what split could I use to get it to work? > > > Note:, I know that I could just fix it by removeing the <br> lines > > after it is done from the array, but it seems that the regular > > expression in split should work. > > Interesting. Docs say: > > If pattern is a String, then its contents are used as the delimiter > when splitting str. If pattern is a single space, str is split on > whitespace, with leading whitespace and runs of contiguous whitespace > characters ignored. > > If pattern is a Regexp, str is divided where the pattern matches. > Whenever the pattern matches a zero-length string, str is split into > individual characters. > > Which seems to be saying exactly what you are are describing. If a > regexp is used the match isn't "eaten", but simply divided on. > > You could split it on "<br>" and then remove any blank elements... not > sure if that's any better than your alternative approach though.- Hide quoted > text - > > - Show quoted text -
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