Lasse, It doesn;t inherit anything:
class Ruport::Controller ... -R.Vince On Apr 15, 3:20 pm, Lasse Bunk <[email protected]> wrote: > Hi R. Vince, > > What does RuportController inherit from? > > /Lasse > > 2010/4/15 RVince <[email protected]> > > > I have data, :current_user, in my Application Controller: > > > class ApplicationController < ActionController::Base > > helper_method :current_user > > private > > def current_associate > > return @current_associate if defined?(@current_associate) > > �...@current_associate = current_associate_session && > > current_associate_session.record > > end > > end > > > , so it is inherited by the controllers that inherit > > ApplicationController > > > I have a module, which is 'required' by several controllers who > > inherit from ApplicationController. One of controllers is descended > > from Application Controller -- another is not (it is descended from > > RuportController). The latter needs to access :current_user. > > > What is the best way to accomplish this? (I have tried > > setting :current_user in the module, so that the controller that is > > derived from RuportController might be able to call the module to > > obtain it, with no luck). > > > Ultimately, I need to get :current_user into the controller derived > > from RuportController -- but how? > > > Thanks, R.Vince > > > -- > > You received this message because you are subscribed to the Google Groups > > "Ruby on Rails: Talk" group. > > To post to this group, send email to [email protected]. > > To unsubscribe from this group, send email to > > [email protected]<rubyonrails-talk%[email protected]> > > . > > For more options, visit this group at > >http://groups.google.com/group/rubyonrails-talk?hl=en. -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en.
