> Michael Pavling wrote:
>
> You need to iterate over a's bs [1] collection, and return the related
> cs. Then probably only return uniq c records (a given c might be
> linked to more than one b...)
> This should give you what you want:
>
> cs=[]
> a.bs.each do |b|
> cs += b.cs
> end
> cs.uniq!
This is the solution that I don't like to use
>
> and this is the same thing:
> a.bs.inject {|cs, b| sum + b.cs }.uniq
>
this looks interesting ! (even if I have to brush up 'inject' :) )
but I am looking for a more simpe solution
thank you,
Alessandro DS
> [1] This is why convention prefers Foo/Bar for example names.... "a,
> b, c" doesn't make for easy or understandable reading.
Yes, I agree with you (the pluralization of A,B,C is unreadable)
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