Should be other_times.day

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On 5 Jan 2011, at 21:10, Fernando Leandro <[email protected]> wrote:

> Hum...  i tried it.. but i always get this sql error 
> 
> #1054 - Unknown column 'other_times' in 'field list' 
> 
> do u know what can be that error?
> 
> Thanks
> 
> 2011/1/5 Frederick Cheung <[email protected]>
> 
> 
> On Jan 5, 8:31 pm, Fernando Leandro <[email protected]>
> wrote:
> > djangst,
> >
> > hum.... but actually in my database it occurs... that are some coursers that
> > have two times that reffers to the same day (because actually in my db, time
> > has the hour too, not only the day)
> >
> > but, using Fred`s example, i would have to make a select in the courses and
> > use that another select that fred used as a condition for this first select?
> >
> > like this?
> >
> > SELECT DISTINCT courses. *
> > FROM courses
> > INNER JOIN courses_times ON courses_times.course_id = courses.id
> > INNER JOIN times ON courses_times.time_id = times.id
> > AND times.dia = 'Monday'
> > WHERE EXISTS (
> >
> > SELECT count( * ) AS times_scheduled
> > FROM courses_times
> > INNER JOIN courses_times AS other_times ON other_times.course_id =
> > courses_times.course_id
> > WHERE courses_times.time_id = times.id
> > GROUP BY courses_times.course_id
> > HAVING times_scheduled =1
> > )
> 
> I think you can do it with a similar query to my first, something
> along the lines of
> 
> select *, count(distinct other_times) as days_scheduled from
> course_times
> inner join times on course_times.time_id = times.id
> inner join course_times as other_course_times on
> course_times.course_id = other_course_times.course_id
> inner join times as other_times on other_times.id =
> other_course_times.time_id
> 
> where times.day = 'Monday'
> group by course_id
> having days_scheduled = 1
> 
> You select course_times whose corresponding time has a day of monday.
> You then join the course_times and times of the same course_id and
> count the number of distinct days. In general, if you can write
> something without a dependant subquery, then you should.
> 
> Fred
> 
> >
> > Sorry for the question but i`m new to sql and all this stuff..
> >
> > Thanks
> >
> > Fernando
> >
> > 2011/1/5 djangst <[email protected]>
> >
> >
> >
> > > Check out Fred's earlier example. Using the count of courses with only
> > > one courses_times row in conjunction with the having clause you can
> > > filter out courses scheduled on more than one day.
> >
> > > The only potential problem I could foresee with this would be if a
> > > course could be scheduled for multiple times on the same day. But
> > > that's not reflected in the data model you posted so it shouldn't be
> > > an issue.
> >
> > > On Jan 5, 1:50 pm, Fernando Leandro <[email protected]>
> > > wrote:
> > > > yes.. its exactly this... but how can i do that in another way?
> >
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