On Nov 23, 3:05 pm, Julie May <[email protected]> wrote:
> From your comment it looks like I may need to understand why I would need
> to assign values return is already part of the text so my assumption is
> that I just have to .to_sym it. However, if I have to assign and deliver
> something that would change quite a bit.
Calling .to_sym on a string returns a NEW symbol. It does exactly
nothing to the string you called it on.
>
> Clarification.
>
> The desired resulting line is:
> ele.send_keys('Student One', :return, 'Student Two', :return)
> Basically "'Student One', :return, 'Student Two', :return" is parsed to
> result in itself except with the symbols understood as symbol type.
>
> In the original:
> x[0] == 'Student One'
> ', ' is added since it is not the last element
> x[1] == 'return' output as x[1].to_sym which adds the : itself.
> ', ' is added since it is not the last element
>
> Pattern repeats.
No. You don't need to put commas in when you're splatting an array. An
example:
def foo(arg1, arg2, arg3)
puts "arg1 is #{arg1.inspect}"
puts "arg2 is #{arg2.inspect}"
puts "arg3 is #{arg3.inspect}"
end
a = [1,2,3]
Then calling:
foo(*a)
will result in:
arg1 is 1
arg2 is 2
arg3 is 3
> Mat, your idea has made the :return do what it is supposed to but now I'm
> unable to get the text to output. All that is coming out is the symbols
> even though puts on the text line shows it should be displaying in the
> following:
> (I added .to_s even though I shouldn't have to just to be sure the type
> hadn't changed.)
>
> items = text.split(/,\s?/)
> ele.send_keys(*items.map {|x|
> case x
> when /^.*'.*/ then $1.to_s+', '
$1 is not being set here - it's used to capture the first set of
parentheses in a regular expression. Your regex is missing them.
> when /^:(.*)$/ then $1.to_sym # ":return" => :return
> else $1.to_s #return unknowns as is
> (nothing should hit this)
Again, $1 will not be set here. x.to_s would be a suitable default.
> I also am unsure how the case structure can detect if the element is 'last'
> so that it doesn't add the comma on the last element.
No commas needed. :)
I highly recommend you check out Programming Ruby (aka "The Pickaxe")
- or at least the first edition of it, available free here:
http://www.ruby-doc.org/docs/ProgrammingRuby/
--Matt Jones
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