On 23/06/2011 10:19, Wolfgang Laun wrote:
Well, you are saying that if you are using references to fact objects
in combination with constraints comparing such a reference to some
other object any (overridden) hashCode method /*must not refer to
mutable fields*/ of that object.
hashCode method /*must not refer to mutable fields*/ of that object.
That's not a good idea really. Hashcode's should refer to fields that
you constrain on, as a general good rule. and those fields are normally
mutable.
I don't really know what more to say than...
Nested accessors are "black box" if you modify a nested accessor you
must notify the root object(s) that are inserted into the engine.
If you want to write up some paragraphs talking people through how
hashcode's and hashmap's work. Specifiically if you change the hashcode
of an object that is in map you won't be able to find it in the map any
more - which is what is happening to you. Notification effectively takes
the root object out and put's it back in again, so it lives in the
correct index.
This is why other engines don't support Objects as fields, you can only
use values - strings, numbers etc. For them it's worse though, they have
to use techniques like shadow facts otherwise they get memory corruption
- but shadow facts only work on direct values, and cannot shadow objects
and nested fields. If you tried to do this stuff in other engines they
would just get corrupted. It's only because we do a tree-graph based
rete network for assymetrical retract that we can allow you to do this
without corruption, but you must still notify the engine.
Mark
Certainly: this restriction should not hurt - I'm inclined to regard
mutable hashCode methods as "suspicious" anyway.
But, nevertheless, it deserves a short paragraph in the "Expert"
manual, don't you think so?
Cheers
Wolfgang
On 23 June 2011 10:50, Mark Proctor <mproc...@codehaus.org
<mailto:mproc...@codehaus.org>> wrote:
On 23/06/2011 09:32, Wolfgang Laun wrote:
If I have
class Type {
int field;
setField( int f ){ field = f; }
}
and do
modify( $type ){ setField( 42 ) }
where is there a "nested accessor"?
$one: One()
$two: Two( $x: one == $one )
If you change a field on object "one". that field is a nested
accessor to Two.
one.field1 = "x"
is the same as doing
two.one.field1 = "x"
so to "two" changing the field of 1 is a nested accessor.
Think about how indexing works.
left == right
when two objects are == each other indexing creates a bucket for
the left and a bucket for the right. If you change the hashcode of
the one on the right, how will it find the bucket on the left?
Mark
-W
On 23 June 2011 10:24, Mark Proctor <mproc...@codehaus.org
<mailto:mproc...@codehaus.org>> wrote:
On 23/06/2011 07:03, Wolfgang Laun wrote:
Eeek!
Assume this: A is a field of B is a field of C is a field of
D is a...
Object references remain the same, in all objects; I simply
modify A, and
"when you change [A] you are also changing [B], so I must
notify the
engine for [B]" but that's a field of C... D... E... and so
on, until
'I' for infinity?!
_*/It's just a change in some fact object's hashCode that
causes this problem./*_
If you don't want any indexing in your rule engine. If you
want indexing, you have to notify the engine. Changes to
nested accessors have always been invisible to the engine. If
a nested access changes, you must notify the engine of the
root fact.
Mark
-W
On 22 June 2011 22:37, Mark Proctor <mproc...@codehaus.org
<mailto:mproc...@codehaus.org>> wrote:
> As One is a field of Two. When you change One you are also
changing Two, so
> you most notify the engine for Two too.
>
> MArk
> On 22/06/2011 14:37, Wolfgang Laun wrote:
>
> To avoid misunderstandings: yes, equals() is written
according to hashCode,
> i.e., according to the usual Java conventions.
>
> If
>
> - an object of class Two contains a member of class
One, and
> - one object Two and one object One are facts, and
> - a rule modifies One, changing its hashCode
>
> then
>
> another rule containing the patterns
> $one: One()
> $two: Two( $x: one == $one )
>
> does NOT fire (any more).
>
> If you use the constraint
> one == $one || != $one
> the rule will fire, and you can observe that hashCode
results for $one and
> $x are the same and that $one.equals( $x ) returns true.
>
> Reproduced using 5.1.1 and 5.2.x
>
> -W
>
>
>
>
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