Swindells, Thomas wrote:
> 
> Can you split it into two separate diverges?
> Diverge to B first and always follow the other path which then does the A
> & C,
> Similarly at the other end wait for A &C and then a second wait to add in
> the condition for B.
> 
> Thomas
> 

I am not sure I entirely follow your suggestion. A, B, & C could fire in any
combination, but always at least one.

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