You can simplify the query:
query "sortedItems"
TreeMap( $values: values() )
from accumulate( $f: Fact(),
init( TreeMap map = new TreeMap(); ),
action( map.put(factKey($f), $f); ),
reverse( map.remove(factKey($f)); ),
result( map ) )
end
-W
On 28 November 2011 10:58, Syargey <[email protected]> wrote:
> I don't want to sort facts outside of drools rules. The sorting is part of
> business requirements. My opinion is that is not a good thing to keep parts
> of business logic in different places.
>
> I spent some time to figure out how it is possible to sort a collection of
> facts and here is my solution:
> ---------------------------
> function String factKey(Fact f)
> {
> return String.format( "%010d~~%s~~%s", f.getRank(), f.getName(),
> f.getValue() );
> }
>
> query sortFactsQuery
> $factsMap: HashMap()
> from accumulate( $f: Fact(),
> init( HashMap map = new HashMap(); ),
> action( map.put(factKey($f), $f); ),
> reverse( map.remove(factKey($f)); ),
> result( map ) )
> $sortedKeyList: TreeSet()
> from collect( String() from $factsMap.keySet() )
> $sortedFacts: List()
> from accumulate( $key: String() from $sortedKeyList,
> collectList( $factsMap.get( $key )
> ) )
> end
> -----------------------
>
> --
> View this message in context:
> http://drools.46999.n3.nabble.com/facts-custom-sort-tp3538410p3541805.html
> Sent from the Drools: User forum mailing list archive at Nabble.com.
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>
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