Each (not *the*) Recommendation with the maximum recommValue can be found using
$recMax: Recommendation( slot == 1, $recommValue: recommValue) not Recommendation( slot == 1, recommValue > $recommValue ) with $recMax being bound to one of the Recommendations with the maximum, and the maximum value being bound to $recommValue. -W On 24 November 2012 13:18, raffi <[email protected]>wrote: > Hello, > > I have a problem with using the /from accumulate/ statement. It is because > I'd like to optmize my code a liitle bit. There are two rules that I like > to > merge. > > /query "max recomm value for slot 1" > accumulate (Recommendation(slot == 1, $recomm_value : recommValue), > max : max($recomm_value)) > end/ > > and > > /query "recomms for slot 1" > recomm : Recommendation(slot == 1) > end/ > > So with the first rule I get the maximum of the variable recommValue. The > second rule is for searching exactly this Recommendation-fact with this > value. Now I tried to merge them in the following way: > / > query "recomm for slot 1" > $recomm : Recommendation() from > accumulate(Recommendation( > slot == 1, $recomm_value : > recommValue), > max($recomm_value) > ) > end/ > > But the returned value always is a double one. Is it because of the usage > of > the maximum function? Is it possible to solve this problem with only one > query (getting that Recommendation-fact with the highest recommValue)? > > Regards... > > > > -- > View this message in context: > http://drools.46999.n3.nabble.com/using-from-accumulate-with-wrong-return-type-tp4020957.html > Sent from the Drools: User forum mailing list archive at Nabble.com. > _______________________________________________ > rules-users mailing list > [email protected] > https://lists.jboss.org/mailman/listinfo/rules-users >
_______________________________________________ rules-users mailing list [email protected] https://lists.jboss.org/mailman/listinfo/rules-users
