Thank you. How to check whether the last line is not empty?
Because line.split_char('\t') would not make sense to run on an empty line.
In python I did it in the following way:
with open(args.output, 'r') as outfile:
for line in infile:
try:
parts = [part.strip() for part in line.split('\t')]
except IndexError:
continue
On Tue, Apr 3, 2012 at 8:36 PM, Mohd. Bilal Husain <[email protected]>wrote:
> As you figured out, the function read_line can be used from the
> reader_util implementation from module io
>
> ~~~~
>
> import io::reader_util;
>
> #[doc = "reads the entire file line by line except the first line"]
> fn main(args: [str]) {
> if args.len() == 1u {
> fail #fmt("usage: %s <filename>", args[0]);
> }
>
> let r = io::file_reader(args[1]); // r is result<reader, err_str>
> if result::failure(r) {
> fail result::get_err(r);
> }
>
> let rdr = result::get(r);
> rdr.read_line(); // skip line
> while !rdr.eof() {
> io::println(rdr.read_line());
> }
> }
> ~~~~
>
> I don't think Rust lets you catch exceptions while reading the stream as
> you can't do much about it*.
>
> * Error handling in Rust is unrecoverable unwinding
>
> On 3 April 2012 13:34, Mic <[email protected]> wrote:
>
>> Hello,
>> I found read_line, but I do not how to convert the following Python code
>> (skip first line and print all other lines from a file) to Rust.
>>
>> f = open(file_name, 'r')
>> f.next() #skip line
>> for line in f:
>> print line
>> f.close()
>>
>> How rust handle exceptions?
>>
>> Thank you in advance.
>>
>> _______________________________________________
>> Rust-dev mailing list
>> [email protected]
>> https://mail.mozilla.org/listinfo/rust-dev
>>
>>
>
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