the "issue-2185.rs" test was xfailed with a ref to #2263. Issue #2263 is now
fixed, so I tried it again, and after adding some &self parameters, I got this
error:
Running /usr/local/bin/rustc:
issue-2185.rs:24:0: 26:1 error: conflicting implementations for a trait
issue-2185.rs:24 impl iterable<uint> for @fn(&fn(uint)) {
issue-2185.rs:25 fn iter(&self, blk: &fn(v: uint)) { self( |i| blk(i) ) }
issue-2185.rs:26 }
issue-2185.rs:20:0: 22:1 note: note conflicting implementation here
issue-2185.rs:20 impl<A> iterable<A> for @fn(&fn(A)) {
issue-2185.rs:21 fn iter(&self, blk: &fn(A)) { self(blk); }
issue-2185.rs:22 }
… so it looks like it's just not possible to implement both the generic
iterable<uint> and iterable<A> for the type iterable<uint>. Is it okay if I
just remove this test?
John
(text of slightly-patched issue-2185.rs follows:)
// Copyright 2012 The Rust Project Developers. See the COPYRIGHT
// file at the top-level directory of this distribution and at
// http://rust-lang.org/COPYRIGHT.
//
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
// option. This file may not be copied, modified, or distributed
// except according to those terms.
// xfail-fast
// This test had to do with an outdated version of the iterable trait.
// However, the condition it was testing seemed complex enough to
// warrant still having a test, so I inlined the old definitions.
trait iterable<A> {
fn iter(&self, blk: &fn(A));
}
impl<A> iterable<A> for @fn(&fn(A)) {
fn iter(&self, blk: &fn(A)) { self(blk); }
}
impl iterable<uint> for @fn(&fn(uint)) {
fn iter(&self, blk: &fn(v: uint)) { self( |i| blk(i) ) }
}
fn filter<A,IA:iterable<A>>(self: IA, prd: @fn(A) -> bool, blk: &fn(A)) {
do self.iter |a| {
if prd(a) { blk(a) }
}
}
fn foldl<A,B,IA:iterable<A>>(self: IA, b0: B, blk: &fn(B, A) -> B) -> B {
let mut b = b0;
do self.iter |a| {
b = blk(b, a);
}
b
}
fn range(lo: uint, hi: uint, it: &fn(uint)) {
let mut i = lo;
while i < hi {
it(i);
i += 1u;
}
}
pub fn main() {
let range: @fn(&fn(uint)) = |a| range(0u, 1000u, a);
let filt: @fn(&fn(v: uint)) = |a| filter(
range,
|&&n: uint| n % 3u != 0u && n % 5u != 0u,
a);
let sum = foldl(filt, 0u, |accum, &&n: uint| accum + n );
io::println(fmt!("%u", sum));
}
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