Good afternoon Phillippe,
Here's how to do it, assuming you're using rust 0.8 and the json library:
```
#[feature(managed_boxes)];
extern mod extra;
use std::io::mem::MemWriter;
use extra::serialize::{Encoder, Encodable};
use extra::json;
pub fn memory_encode<
T: Encodable<json::Encoder>
>(to_encode_object: &T) -> @mut MemWriter {
//Serialize the object in a string using a writer
let m = @mut MemWriter::new();
let mut encoder = json::Encoder(m as @mut Writer);
to_encode_object.encode(&mut encoder);
m
}
fn main() {
}
```
Regarding the trouble returning a `MemWriter` instead of a `@mut
MemWriter`, the easiest thing would be to fix library to use `&mut ...`
instead of `@mut ...`. I'll put in a PR to do that.
On Thu, Nov 28, 2013 at 3:55 AM, Philippe Delrieu
<[email protected]>wrote:
> I try to develop a function that take a Encodable parameter but I have the
> error wrong number of type arguments: expected 1 but found 0
>
> pub fn memory_encode(to_encode_object: &serialize::Encodable) -> @mut
> MemWriter {
> //Serialize the object in a string using a writer
> let m = @mut MemWriter::new();
> let mut encoder = Encoder(m as @mut Writer);
> to_encode_object.encode(&mut encoder);
> m
> }
>
> The encodable trait is :
> pub trait Encodable<S:Encoder> {
> fn encode(&self, s: &mut S);
> }
>
> I try this definition
> memory_encode<T:serialize::Encodable<Encoder>>(to_encode_object: &T) ->
> @mut MemWriter
>
> But I can't use the method with a struct that implement Encodable. The
> error : mismatched types: expected `&<V31>` but found ..
>
> I have another question :
> I would like to return a MemWriter and not a @mut MemWriter . I didn't
> find a way to convert the @mut to ~
>
> Philippe Delrieu
> _______________________________________________
> Rust-dev mailing list
> [email protected]
> https://mail.mozilla.org/listinfo/rust-dev
>
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