Can't you put that outside your inner loop?
On Mar 26, 2014 5:15 PM, "Phil Dawes" <rustp...@phildawes.net> wrote:
> Hello everyone!
>
> I'm interested in using rust for latency sensitive applications. What's
> the cheapest way to achieve isolation in a native rt environment?
>
> I'd like to do something like:
>
> let result: Result<Foo, ()> = task::try(proc() {
> ... potentually failing code ...
> });
>
> but as cheaply as possible and without spawning a thread. Should I attempt
> to implement a new type of task that runs immediately in the same OS thread
> or is there another way to achieve the same isolation?
>
> Many thanks,
>
> Phil
>
>
>
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