Hello,
I have a problem in my code and I can't find a solution. I develop a
test case that generate the same error. Any idea?
use std::vec::Vec;
use std::rc::Rc;
use std::cell::RefCell;
struct Test;
impl Test {
fn match_fn<'a>(&'a self) ->Option<&'a Test> {
None
}
fn test_mutable<'a>(&'a mut self, test: &'a Test) {}
}
fn TestMatchBorrow() {
let mut viewList: Vec<~Test> = Vec::new();
for ref mut test in viewList.mut_iter() {
match test.match_fn() {
Some(mut borrow_test) => test.test_mutable(borrow_test),
None => {},
}
}
}
#[main]
fn main() {
TestMatchBorrow();
}
The test struct can't be changed.
If I don't put the borrow_test in test.test_mutable(borrow_test) it compile.
The error :
test_match.rs:22:38: 22:42 error: cannot borrow `***test` as mutable
because it is also borrowed as immutable
test_match.rs:22 Some(mut borrow_test) =>
test.test_mutable(borrow_test),
^~~~
test_match.rs:21:15: 21:19 note: previous borrow of `***test` occurs
here; the immutable borrow prevents subsequent moves or mutable borrows
of `***test` until the borrow ends
test_match.rs:21 match test.match_fn() {
^~~~
test_match.rs:24:10: 24:10 note: previous borrow ends here
test_match.rs:21 match test.match_fn() {
test_match.rs:22 Some(mut borrow_test) =>
test.test_mutable(borrow_test),
test_match.rs:23 None => {},
test_match.rs:24 }
Philippe
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