Hi,
On Sun, 7 Sep 2014 17:49:39 +0800
Che-Wei Lin <[email protected]> wrote:
> On Ubuntu python's stdlib socket.gethostbyname return 127.0.1.1 NOT
> 127.0.0.1
?
http://serverfault.com/questions/363095/why-does-my-hostname-appear-with-the-address-127-0-1-1-rather-than-127-0-0-1-in
> Python 2.7.6 (default, Mar 22 2014, 22:59:56)
> [GCC 4.8.2] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
>>>> import socket
>>>> socket.gethostbyname(socket.gethostname())
> '127.0.1.1'
>
> It will cause the connect fail on Ubuntu, but Mac OS X can work normally
>
> Python 2.7.8 (default, Aug 24 2014, 21:26:19)
> [GCC 4.2.1 Compatible Apple LLVM 5.1 (clang-503.0.40)] on darwin
> Type "help", "copyright", "credits" or "license" for more information.
>>>> import socket
>>>> socket.gethostbyname(socket.gethostname())
> '192.168.111.105'
>
> I tried to bind(('0.0.0.0', port)) but it return 127.0.0.1 either Mac OS X
> or Ubuntu.
> Remote client (Snort machine side) can't connect to 127.0.0.1.
I'm not sure we are on the same page. I just meant that bind() with
"0.0.0.0" accepts a connnection via any host's ip address. To make
clear, I've attached simple code.
> I also found another way to get host IP but need additional installs
> package netifaces. (https://pypi.python.org/pypi/netifaces)
>
> Or, maybe let someone config controller IP address in applications?
>
>
> Che-Wei Lin <http://about.me/linton.tw>, John Lin
> Institute of Communication Engineering,
> National Tsing Hua University
> [image: 林哲緯 on about.me]
> E-mail: [email protected]
> Blog: blog.linton.tw
> Mobile: +886-952-301-269
>
>
> On Sun, Sep 7, 2014 at 3:44 PM, FUJITA Tomonori <
> [email protected]> wrote:
>
>> Hi,
>>
>> On Sun, 7 Sep 2014 15:34:02 +0800
>> Che-Wei Lin <[email protected]> wrote:
>>
>> > I fixed some trivial minor bug and corrected some typos in the document.
>> >
>> > I found that when i want to get the REAL IP.
>> > The old version used on Ubuntu python's stdlib socket.gethostbyname
>> return
>> > 127.0.0.1.
>>
>> I guess that a host can have multiple real IP addresses and 127.0.0.1
>> is one of them.
>>
>> If I understand your code correctly, you try to connect to 8.8.8.8 and
>> use the address to access to 8.8.8.8 for binding a listen port. I'm
>> not sure if it is a good idea because:
>>
>> 1) A host could not access to the internet (8.8.8.8) due to many
>> reasons (firewall, etc).
>>
>> 2) Even a host can, the address for accessing to the Internet is not
>> appropriate for a listen port for this application.
>>
>> Why not?
>>
>> bind(('0.0.0.0', port))
>>
>> > This patch I am using another way to get the real IP
>>
import socket
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
serversocket.bind(("0.0.0.0", 8080))
serversocket.listen(5)
(clientsocket, address) = serversocket.accept()
print "accept a new connection", clientsocket.getpeername()
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