On 2012-12-05, Andrew Mathas <andrew.mat...@sydney.edu.au> wrote: > ------=_Part_33_6944284.1354751535501 > Content-Type: text/plain; charset=ISO-8859-1 > > Here's a related question: suppose I have an object G in sage. Is there a > "correct" way to ask G if is it a CombinatorialFreeModule? I can check for > > if hasattr(G,'_basis_keys'): ... > > but I would have thought that there was a better way to do this... isinstance?
sage: F = CombinatorialFreeModule(QQ, ['a','b','c']) sage: isinstance(F,CombinatorialFreeModule) True sage: isinstance([],CombinatorialFreeModule) False HTH, Dima > > Andrew > -- You received this message because you are subscribed to the Google Groups "sage-combinat-devel" group. To post to this group, send email to sage-combinat-devel@googlegroups.com. To unsubscribe from this group, send email to sage-combinat-devel+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sage-combinat-devel?hl=en.
