Hi all, I am sure some of you have been thinking about that before:
sage: a = Permutation([3,2,1]) sage: b = Partition([3,2,1]) sage: c = Composition([3,2,1]) sage: a == b == c True sage: hash(a) == hash(b) == hash(c) True Is this desired behaviour? Thanks, Christian -- You received this message because you are subscribed to the Google Groups "sage-combinat-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-combinat-devel+unsubscr...@googlegroups.com. To post to this group, send email to sage-combinat-devel@googlegroups.com. Visit this group at http://groups.google.com/group/sage-combinat-devel. For more options, visit https://groups.google.com/groups/opt_out.
