Yes, GF(p)[x] uses NTL.

On Feb 1, 2007, at 12:47 PM, Joel B. Mohler wrote:

> On Thursday 01 February 2007 14:28, Martin Albrecht wrote:
>> There is a specialized implementation for polynomials over Z mod N  
>> which is
>> faster than the generic implementation which is used for GF(2^3).  
>> This is
>> certainly fixable (by writing a specialized implementation for GF 
>> (p^n).
>>
>> Does this help?
>
> That seems quite reasonable.  I'm able to do what I want to do for  
> the moment.
> If I want more, I will pursue this route.  Thanks.
>
> --
> Joel
>
> 

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