Thanks for reporting the bug. I opened trac ticket #34733 <https://trac.sagemath.org/ticket/34733> for this.
On Tuesday, November 8, 2022 at 3:20:51 AM UTC-7 pkopr...@pkoprowski.eu wrote: > Hello everyone, > > I just discovered a bug in the polynomial division over quaternion > algebras. I don't see it discussed anywhere on the internet, so I believe > this is a proper place to report it. > > Bug description: the quo_rem method for polynomials with quaternionic > coefficients outputs incorrect results. Moreover, there is no way to > specify whether we want a right or left division. Here is a specific > example. > > # Take the quaternion algebra (-1, -1)_QQ and the ring of polynomials over > it: > HH = QuaternionAlgebra(QQ, -1, -1) > P.<x> = HH[] > # Take two polynomials > f = x^3 + HH.0*x + (HH.1 + 2*HH.2); print("f =", f) > g = HH.2*x + HH.1 + 3; print("g =", g) > # Try to compute the quotient and remainder > q, r = f.quo_rem(g) > # Check the correctness of the result assuming that this is RIGHT division > print(q*g + r == f) > # Check the correctness of the result assuming that this is LEFT division > print(g*q + r == f) > > Both tests output False. Tested on Sage 9.5. > > Mathematical background: the division with the remainder for polynomials > over division rings is well known and fully described e.g. in [1] even in a > more general setting when the variable does not commute with the > coefficients (in our case it does commute). So it is just a matter of > proper implementation. > > *[1] Ore, Oystein*. Theory of non-commutative polynomials. *Ann. of Math. > (2)* * 34 * (1933), no. 3, 480--508. MR1503119 > <https://mathscinet.ams.org/mathscinet-getitem?mr=1503119> > > > > -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-devel+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sage-devel/663c1350-770f-467b-b9af-7275af6a47d7n%40googlegroups.com.