> Isn't it the case that actually p.subs(x2=x2) is *equivalent* to p.subs
> ({'x2':x2}) in Python?
No, this isn't the same in Python. You are looking for:
sage: R.<x0,x1,x2>=QQ[]
sage: S = QQ['x0,x1,x2,x3']
sage: p=S.random_element()
sage: p.subs(x2=x2)
and
sage: p.subs(**{'x2':x2})
-7/2*x1*x2 + 1/2*x2^2 - x0*x3 + 1/165*x1 + 3
Note the two stars. The reason why the subs function accepts a dictionary is
that its signature is:
p.subs(self, fixed, **kw=None)
i.e. it also accepts a dictionary 'fixed'. This dictionary expects its keys to
be variables and not strings of variable names.
Cheers,
Martin
--
name: Martin Albrecht
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_jab: [email protected]
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