Consider
sage: G = SymmetricGroup(2)
sage: elements = G.list()
sage: elements.remove(G("()"))
sage: K = SymmetricGroup(2)
sage: K.list()
[(1,2)]
Notice K lacks the identity permutation. I'd at least expect K to
be a "new" undisturbed version of S_2.
Is there some overly-aggressive caching here? Should there be some
protection against the above? Or am I missing something?
Using elements = copy(G.list()) causes K to have all of its
elements, but the docstring for list() doesn't say anything about
making a copy, or being an "in-place" version, etc.
Rob
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