det FUNCTION IS HAVING A VERY ANNOYING BEHAVIOR,GIVEN THE ATTACHED MATRIX FOR EXAMPLE IF I TRY TO GET THE DETERMINANTS WITH TWO DIFFERENT METHODS:
sage: M=load(PATHTOFILE + '/M.sobj') sage: M.det() 6.49037107316853e32 sage: from numpy import linalg sage: linalg.det(M) -1.5055380070396349e-05 THE SECOND RESULT IS CORRECT (THE MATRIX IS SINGULAR). THE DEFAULT det FUNCTION SEEMS TO OVERFLOW WITh A MATRIX OF JUST 20 ROWS? IS THIS A BUG? -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-devel?hl=en.
M.sobj
Description: Binary data
