Hello, I have to use Sage from an external comand and in order to do so I'll need to rely on the exit status given by Sage. Considering a trivial example
============= $ cat foo.sage exit(0) ============= I get the following behaviour ============= $ sage la.sage 0 $ echo $? 1 ============= There are two things I am confused with here. 1. Why do we print 0? 2. Why is the exit status 1 - indicating an error by UNIX standards? Is there any reason behind this? If yes , what would be the best way to force my own exit status so that I can interpret the execution of Sage from an external program? Best, Jernej -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-devel. For more options, visit https://groups.google.com/d/optout.
