how about making GF(16) default to GF(16,'conway')
no symbols injected, no conflicts...


On Wednesday, 20 January 2016 21:28:21 UTC, Nils Bruin wrote:
>
> On Wednesday, January 20, 2016 at 1:04:49 PM UTC-8, John Cremona wrote:
>
>>
>> > Is there any reason to not make GF(16) behave as GF(16,'x') does,
>> > unless specified otherwise? I do not see the point of requesting the
>> > user to provide a character if (s)he does not care.
>> >
>>
>> +1 for having a default, though I would choose 'a'.
>>
>>
> There is a potential confusion there:
>
> sage: ZX.<x>=ZZ[]
> sage: ZY.<y>=ZZ[]
> sage: F=GF(16,'x')
> sage: R=F['x,u,v']
> sage: S=F['y,u,v']
> sage: S(x).degree()
> 0
> sage: R(x).degree()
> 1
> sage: S(y).degree()
> 1
> sage: R(y).degree()
> 0
>
> This is actually a bit of a mess: generator names are supposed to be used 
> in figuring out coercion maps, but currently this doesn't seem to happen 
> too much with GF(p^r) . [Really, F(y) should be an error, because it's 
> totally not clear where y should go]. So currently, having a default name 
> in GF doesn't seem to be too much of an issue because GF violates normal 
> coercion rules. However, if this were fixed then a default generator name 
> (especially when it's something usual such as x) would lead to odd 
> interactions with coercions from various structures.
>

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