sage: def foo():
....: from sage.combinat.posets.poset_examples import Posets
....: from sage.misc.functional import log
....: P = Posets.BooleanLattice(3); n = P.cardinality(); s =
P._hasse_diagram.size()
....: if 2*s > n*log(n, 2): print "True"
....:
sage: foo()
sage:
So, in this case the comparison is False. Now when I add exactly same
function on end of lattices.py and compile I got
sage: sage.combinat.posets.lattices.foo()
True
sage:
What's wrong? Somehow comparison and logaritms don't mix (again).
* * *
Is there a function to get 2-based logarithm of integer in Sage? In Python
3.3 there is, but we use Python 2.x.
--
Jori Mäntysalo
