Dear all, on sage8.2 when I do 1] var('a1 a2 a3 ap1 ap2 ap3 b1 b2 b3 bp1 bp2 bp3 k')
solve([ a1 == 1, a2 == 2, a3 == 1, ap1 == 1, ap2 == 1, ap3 == 2, *a1*bp1-ap1*b1 == a2*bp2-ap2*b2 == -(a3*bp3-ap3*b3) == k,* a1*bp2+a2*bp1-ap2*b1-ap1*b2==0, a1*bp3+a3*bp1-ap3*b1-ap1*b3==0, a2*bp3+a3*bp2-ap3*b2-ap2*b3==0, ],a1,a2,a3,ap1,ap2,ap3,b1,b2,b3,bp1,bp2,bp3,k) and then I transform 1] to 2] (see bold char.) solve([ a1 == 1, a2 == 2, a3 == 1, ap1 == 1, ap2 == 1, ap3 == 2, * a1*bp1-ap1*b1==k, a2*bp2-ap2*b2==k -(a3*bp3-ap3*b3)==k,* a1*bp2+a2*bp1-ap2*b1-ap1*b2==0, a1*bp3+a3*bp1-ap3*b1-ap1*b3==0, a2*bp3+a3*bp2-ap3*b2-ap2*b3==0, ],a1,a2,a3,ap1,ap2,ap3,b1,b2,b3,bp1,bp2,bp3,k) --------- why the response of 1 (seems correct to me, since (b1,b2,b3,bp1,bp2,bp3) belongs to 2 dim space. vect) and 2 (seems to me strange, since (b1,b2,b3,bp1,bp2,bp3) belongs to 1 dim space. vect) are so different? I should remain the same. Please advise. Regards, Ken -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-devel+unsubscr...@googlegroups.com. To post to this group, send email to sage-devel@googlegroups.com. Visit this group at https://groups.google.com/group/sage-devel. For more options, visit https://groups.google.com/d/optout.