Dear all,
on sage8.2
when I do

1]
var('a1 a2 a3 ap1 ap2 ap3 b1 b2 b3 bp1 bp2 bp3 k')

solve([
    a1 == 1, a2 == 2, a3 == 1, ap1 == 1, ap2 == 1, ap3 == 2,

    *a1*bp1-ap1*b1 == a2*bp2-ap2*b2 == -(a3*bp3-ap3*b3) == k,*

      a1*bp2+a2*bp1-ap2*b1-ap1*b2==0,
      a1*bp3+a3*bp1-ap3*b1-ap1*b3==0,
      a2*bp3+a3*bp2-ap3*b2-ap2*b3==0,
      ],a1,a2,a3,ap1,ap2,ap3,b1,b2,b3,bp1,bp2,bp3,k)

and then I transform 1] to
2] (see bold char.)


solve([
    a1 == 1, a2 == 2, a3 == 1, ap1 == 1, ap2 == 1, ap3 == 2,



*  a1*bp1-ap1*b1==k,    a2*bp2-ap2*b2==k   -(a3*bp3-ap3*b3)==k,*

      a1*bp2+a2*bp1-ap2*b1-ap1*b2==0,
      a1*bp3+a3*bp1-ap3*b1-ap1*b3==0,
      a2*bp3+a3*bp2-ap3*b2-ap2*b3==0,
      ],a1,a2,a3,ap1,ap2,ap3,b1,b2,b3,bp1,bp2,bp3,k)

---------
why the response of 1 (seems correct to me, since (b1,b2,b3,bp1,bp2,bp3)
belongs to 2 dim space. vect) and 2 (seems to me strange, since
(b1,b2,b3,bp1,bp2,bp3) belongs to 1 dim space. vect) are so different?
 I should remain the same.
Please advise.
Regards,
Ken

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