Hi, I'm very new to Sage, thus it's likely I'm using it wrongly, but is 
this a bug?

Using:
https://sagecell.sagemath.org/

I entered:

F(x)=1/(1 + exp(-x))
FN(x,n) = F(x)**n
assume(n, 'integer')
assume(log(exp(n)+1) - n > 0)
fn = diff(FN(x,n), x)
mean(n) = integral(fn(x, n), (x, 0, oo))
mean(1)

and I get:

1/((e + 1)*log(e + 1)^2 - 2*(e + 1)*log(e + 1) + e + 1)

The answer I would expect is:
1/2


Also, it seems the expression I get as answer could be more compactly formatted 
as:
1/(e + 1)/(log(e + 1) - 1)^2
but that's secondary, the main point being whether the result is correct.

Cheers,
Mihai

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