On Wed, Jul 22, 2009 at 9:08 AM, Mike <[email protected]> wrote: > > Thanks guys, the zip solution worked perfectly. I never thought about > trying that. I'm sure the range solution would of worked too for my > example, but in my real problem the "x" list was the result of an > arctan function, so no real simple pattern the range function could > handle. Thanks again > > > It should've worked, x doesn't neex to be a range
z = [y[i]^x[i] for i in range(len(x))]; it says... i goes from 0 to length(x)-1 i is the "index" or "position" then it gets y's and x's ith-position y[i], x[i] and does whatever operation you indicate --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sage-edu" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-edu?hl=en -~----------~----~----~----~------~----~------~--~---
