Micah <[email protected]> wrote:

Jorge,

For what it's worth, it appears that f(2) and g(-1) are elements of
the symbolic ring, rather than the integer ring. As such, the
equation

sage: f(2)==g(-1)

is not interpreted as "evaluate this as a boolean expression".
Rather, it is interpreted as another symbolic expression. This does
not happen when the two sides of the equation are in the integer ring.

sage: parent(0)
Integer Ring
sage: 0==0
True

but f(2) is 0 in the symbolic ring, thus the equation of symbolics is
interpreted as a symbolic element itself.

sage: parent(f(2))
Symbolic Ring
sage: f(2)==g(-1)
0 == 0
sage: parent(f(2)==g(-1))
Symbolic Ring
sage: SR(0)==SR(0)
0 == 0


As a workaround, I noticed that if you define your functions using
lambda, this does not happen.

sage: f = lambda x:x**2-4
sage: g = lambda x:x**2-2*x+1
sage: parent(f(2))
Integer Ring
sage: f(2)==g(-1)
True


This may not be the ideal way to present the functions to your class,
but it might be better than something of the form
sage: (f(2)-g(-1)).is_zero()


Here's hoping this was helpful!

-Micah



On Sep 21, 2:04 pm, "A. Jorge Garcia" <[email protected]> wrote:
> I had a weird problem in class today. Let's say I had the following
> code in a cell:
>
> f(x)=x**2-4
> g(x)=x**2+2*x+1
> f(2)==g(-1)
>
> What output should I get? I was expecting: True Am I crazy? Needless
> to say I didn't!
>
> TIA,
> A. Jorge 
> Garciahttp://shadowfaxrant.blogspot.comhttp://www.youtube.com/calcpage2009

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I see. I could have swarn that I'd done this before....

Anyway, rather than lambda notation, what if I just define a function like this

def f(x):
return x**2-4

def g(x):
return x**2+2x+1

f(2)==g(-1)
Thanx,
A. Jorge Garcia
Applied Math and CompSci
http://shadowfaxrant.blogspot.com
http://www.youtube.com/calcpage2009
Sent via DROID on Verizon Wireless

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