[EMAIL PROTECTED] wrote:
> I was doing some basic algebra with sage and encountered another
> curiosity. I wish to solve for x in:
>
> |x^2-x| = 3
Your question is not well-defined. If you want real solutions then
x^2-x must =+3 and there are two solutions, from solving a quadratic,
(1+sqrt(13))/2 and the (1-sqrt(13))/2. This hardly needs a computer!
If you want complex solutions then the solutions form a curve in the
complex plane, and what sort of response would you expect?
John Cremona
>
> My naive attempt in sage wasn't so fruitful
>
> sage: eqn = maxima('abs(x^2-x)=3')
> sage: eqn.solve('x')
> [abs(x^2 - x) = 3]
>
> Although, the subproblems are easy enough:
>
> sage: eqn = maxima('x^2-x=-3')
> sage: eqn.solve('x')
> [x = - (sqrt(11)*%i - 1)/2,x = (sqrt(11)*%i + 1)/2]
> sage: eqn = maxima('x^2-x=3')
> sage: eqn.solve('x')
> [x = - (sqrt(13) - 1)/2,x = (sqrt(13) + 1)/2]
>
> How should such a difficulty be attacked? Is this a deficiency of
> maxima?
>
> -carson-
>
> PS: Thanks for the helpful discussion of methods for computing the
> conjugate tranpose of matrices.
>
>
> >
>
--
Prof. J. E. Cremona |
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School of Mathematical Sciences | Fax: +44-115-9514951
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