On 3/30/07, Marshall Hampton <[EMAIL PROTECTED]> wrote:
>
> Here's a function definition to avoid using maxima:
>
> def cross_product(vec1,vec2):
>     r'''
>     This returns the cross product of 2 three-dimensional vectors.
>
>     INPUT:
>         vec1 - the first 3D vector in the cross product
>         vec2 - the second 3D vector in the cross product
>
>     OUTPUT:
>         A 3D vector
>
>     EXAMPLES:
>     basic usage:
>         sage: cross([1,2,3],[2,3,4])

sage: cross_product([1,2,3],[2,3,4])


>         [-1, 2, -1]
>
>     NOTES:
>         This is a crude first attempt.
>     '''
>     x,y,z = QQ['x,y,z'].gens()
>     mat = matrix([[x,y,z],vec1,vec2])
>     d = det(mat)
>     return [d(1,0,0),d(0,1,0),d(0,0,1)]

return [d(1,0,0),-d(0,1,0),d(0,0,1)]

>
>
>
> On Mar 30, 11:33 am, "Marshall Hampton" <[EMAIL PROTECTED]> wrote:
> > Hi,
> >
> > I am not an expert on SAGE but I was curious about your question and
> > tried to find an answer.  I am curious about better ways to do this.
> >
> > Anyway, the first thing I found that works is to use maxima's vect
> > package.  For some reason it uses '~' as the cross-product operator.
> > As an example:
> >
> > sage: maxima.load('vect')
> > ?\/Users\/mh\/sage\ - 2\.1\.0\.1\/local\/share\/maxima\/5\.11\.0\/share
> > \/vector\/vect\.mac
> > sage: maxima('express([1,2,3]~[2,3,4])')
> > [ - 1,2, - 1]
> >
> > At some point it would be nice to have a native SAGE way to do this
> > and other differential form computations; given the developer's
> > interest in modular forms this probably wouldn't be extremely
> > difficult.
> >
> > -M.Hampton
> >
> > On Mar 30, 4:58 am, "microdev" <[EMAIL PROTECTED]> wrote:
> >
> > > hello,
> >
> > > I have tried the dot product :
> >
> > > v = (1,2,3)
> > > v1 = (2,4,6)
> > > v.dot_product(v1) -> ok
> >
> > > and for the cross product?
> >
> > > thank you for help..
> >
> > > Felix
>
>
> >
>

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