You could try substituting x+1 for x first, then do what you want, and
substitute back at the end,
I would expect the auto-simplification to happen at that last step
too, but you would be able to (say) replace x by (x-1) in the textual
output.  I wonder if it is possible to have a variable whose name, as
a string, as "(x-1)"?

John

On 31/01/2008, pgdoyle <[EMAIL PROTECTED]> wrote:
>
>
>
> On Jan 31, 12:29 am, "William Stein" <[EMAIL PROTECTED]> wrote:
> > On Jan 30, 2008 3:48 PM, pgdoyle <[EMAIL PROTECTED]> wrote:
> >
> >
> >
> >
> >
> > > I would like to take the Taylor series of a matrix.  But I find I
> > > can't even put a Taylor polynomial into a matrix without its being
> > > simplified.
> >
> > > sage: f=-x/(2*x-4); f
> > > -x/(2*x - 4)
> > > sage: g=taylor(f,x,1,1); g
> > > 1/2 + x - 1
> > > sage: matrix(1,[g])
> > > [x - 1/2]
> > > sage: m=matrix(1,[f]); m
> > > [-x/(2*x - 4)]
> > > sage: m.apply_map(lambda e: taylor(e,x,1,1))
> > > [x - 1/2]
> >
> > > Any suggestions?
> >
> > You're already doing it exactly correctly.  Try a higher degree
> > approximation to avoid confusion:
> >
> > sage: m = matrix(1,[-x/(2*x-4)])
> > sage: m.apply_map(lambda e: taylor(e,x,1,4))
> > [x + (x - 1)^4 + (x - 1)^3 + (x - 1)^2 - 1/2]
>
> William:
>
> Sorry - I didn't make the issue clear enough.  When I ask for the
> Taylor polynomial at x=1, I want a polynomial in x-1.  And that's what
> I get, except that when I put this polynomial into a matrix, 1/2 + x -
> 1 gets simplified to x-1/2.  Your example shows this behavior very
> clearly.
>
> I understand that a whole new approach to power series is in the
> works, which will keep track of degrees of approximation, and I expect
> this will include taking the power series of a matrix.  But for now, I
> just want to be able to use Sage instead of Mathematica for an
> exposition of generating functions for Markov chains, where I need to
> compute and display Taylor polynomials of matrices.  Hopefully there
> is some way I can keep a polynomial in x-1 from getting simplified
> automatically when it's an element of a matrix.
>
> Cheers,
>
> Peter
>
> Cheers,
>
> Peter
> >
>


-- 
John Cremona

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