Hi,

Yes, I know that for lots of negative real numbers x^x is not defined,
but for some values of x, such as x=-1 or x=-1/3 there is a real
number answer and I don't see anything plotted. Why isn't anythng
plotted at those discrete set of values?

Dan

On May 16, 5:37 pm, Robert Bradshaw <[EMAIL PROTECTED]>
wrote:

>
> This is because x^x is not real-valued for negative x (except at a  
> discrete set of values). Unlike the cube root case, one can't even  
> pick a branch that makes it real-valued.
>
> - Robert
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