> you just overwrote the > previous definition of a which was in the boolean polynomial ring
Ok. Now I understand. > Try A(1) > for the constant 1 in A for which A(1) + A(1) holds. Yes, this works for me. Thanks! On Jun 4, 1:06 pm, Martin Albrecht <[EMAIL PROTECTED]> wrote: > > sage: a=1 > > sage: a+a > > 2-------------------------------------------------> NOT ok: why is > > this not 0? > > because you just set a to the integer 1. Python and Sage are not strongly > typed, so you can assign any type to any variable and you just overwrote the > previous definition of a which was in the boolean polynomial ring. Try A(1) > for the constant 1 in A for which A(1) + A(1) holds. > > Martin > > -- > name: Martin Albrecht > _pgp:http://pgp.mit.edu:11371/pks/lookup?op=get&search=0x8EF0DC99 > _www:http://www.informatik.uni-bremen.de/~malb > _jab: [EMAIL PROTECTED] --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
