Actually this sum can't be done by Maxima, but Derive can do it (even
an old version of derive). do you have an idea of how this problem is
planning to be solved?
On 10 nov, 19:30, "William Stein" <[EMAIL PROTECTED]> wrote:
> On Mon, Nov 10, 2008 at 5:29 PM, cesarnda <[EMAIL PROTECTED]> wrote:
>
> > how could I compute this:
>
> > sum_{ x = 1}^{\infty} 1/x - 1/(x+1)
>
> > or
>
> > sum(1/x-1/(x+1),x,1, infinity)
>
> > directly in Sage, without calling maxima or sympy?
>
> Unfortunately, this isn't implemented yet. See:
>
> http://trac.sagemath.org/sage_trac/ticket/3587
>
> William
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