On Jan 17, 2009, at 10:18 AM, Hinnerk wrote:
> On 15 Jan., 21:00, Robert Bradshaw <[email protected]>
> wrote:
>> The simplified form is cached, so you can use this to fool it into
>> thinking it's already simplified.
>>
>> sage: f = q + 1 + q
>> sage: f._simp = f
>> sage: f
>> q + 1 + q
>
> thank you very much Robert!
>
> Unfortunately this drives show() into endless recursion:
>
> [~2000 lines deleted]
> File "[...]/sage/local/lib/python2.5/site-packages/sage/calculus/
> calculus.py", line 5284, in _latex_
> return self.simplify()._latex_()
> File "[...]/sage/local/lib/python2.5/site-packages/sage/calculus/
> calculus.py", line 5283, in _latex_
> if simplify and not self._has_been_simplified():
> RuntimeError: maximum recursion depth exceeded
Hmm... it looks like the _simp would need to be set all the way down
the tree or something.
> On a sidenote: Even this hack does not return the exact same formular
> given but some mathematically equivalent form:
>
> sage: void = var("a, b, c")
> sage: d = b * (a/c)
> sage: d._simp = g
> sage: d
> b*a/c
It is just opting to not put the ()'s in for printing, as they are
unneeded.
> This seems awfully simple unless one has to explain the transformation
> of a much longer formular to some laymen, which is exactly what I'm
> just trying to escape from.
Perhaps the discussion of a "hold" command that has come up before
would be useful here.
- Robert
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