On Mar 16, 1:52 pm, epple <dedaa...@gmail.com> wrote: > When comparing finite sets, I receive unexpected results. > Version: 3.4 (Sage on the web) > Code: > sage: S=Set([1,2]) > sage: T=Set([3]) > sage: S<T,S>T,S==T > (True, False, False)
As far as I can tell, for Sets, == and != mean what they should, while < and > are not very helpful. (I think that S<T is True if and only if S is not equal to T, while S>T is always False.) > The output seems to be the same whatever I put in for S and T, as long > as I don't make them equal. Is there another easy way to compare two > sets (or the underlying sets of two lists) without writing a routine > for it? Convert S and T to sets (instead of Sets): sage: S.set().issubset(T.set()) or just use Python sets instead of Sage Sets: sage: S = set([1,2,3]) sage: T = set([3]) sage: S.issubset(T) False sage: S.issuperset(T) True sage: T.issubset(S) True Is this the sort of thing you want? --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
