Hi Burcin, On Jan 25, 4:41 pm, Burcin Erocal <bur...@erocal.org> wrote: > ... > In your example, (k1 + k2) is not a subexpression of f, so there is > nothing to substitute.
In other words, (k1+k2)*2 is automatically turned into 2*k1+2*k2, but (k1+k2)^2 is not turned into k1^2+2*k1*k2+k2^2 ? Why? Cheers, Simon -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
