On Tue, Feb 23, 2010 at 10:22 AM, Santanu Sarkar <[email protected]> wrote: > How I calculate the integer part of e^100, where e=1+1/2+1/6+.... i,e > logarithmic e ?
You can take it's floor: sage: floor(e^100) 26881171418161354484126255515800135873611118 --Mike -- To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
