On Feb 28, 5:44 am, Marshall Hampton <[email protected]> wrote:
> I'm not sure this is the best answer, but you could do:
>
> A = matrix(SR,[[a,b],[c,d]])
> v1,v2 = A.eigenvalues()
> show((A-v1).left_kernel().basis()[0])
> show((A-v2).left_kernel().basis()[0])
>
> Perhaps part of the issue is that these do not have to be distinct.

Many thanks, that works. I will use that workaround.

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