Hi everybody again.
Does anybody if it is possible to use the result of the function solve
to insert it in a function to resolve it analitically.
For example, I want to get the peak of the following function
>>> var('tau0,tau1')
>>> f(x) = (1-e**(-x/tau0))*(e**(-x/tau1))
For that, I simply derive it and equal to zero
>>> solve(derivative(f,x)==0,x)
>>> [x == tau0*log(tau1/tau0 + 1), e^(-(tau0 + tau1)*x/(tau0*tau1)) == 0]
I would like to take the first expression of that list
>>> xpeak = solve(derivative(f,x)==0,x)[0]
for example, to calculate its value when tau0=0.5 and tau1=5.0
>>> xpeak.subs(tau0=.5, tau1=5.0)
but this returns a symbolic expresion ,
t == 0.500000000000000*log(11.0000000000000)
and not the scalar 1.1989
More importantly, I would like to use this expression to solve
analytically the y value of that equation as a function of tau0 and tau1
Any suggestion would be greatly appreciated!
Best
Jose.
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