On Fri, Apr 16, 2010 at 2:22 PM, Alec Mihailovs
<[email protected]> wrote:
> On Apr 16, 1:50 pm, Alec Mihailovs <[email protected]> wrote:
>>
>> Or even more simple -if A is the matrix consisting of all non-erased
>> columns, use A.transpose()*(A*A.transpose()).inverse() for decoding,


Do you mean A is the matrix of all n^k codewords, but you remove the
columns corresponding to the erasure positions? I don't know what you
mean by A.


>> applying it to the non-erased part.
>
> And if A*A.transpose() is singular, the same thing, probably, could be
> done with the matrix, obtained from A by removing a column, but I'm
> not sure - there may be, perhaps, cases, when removing more than 1
> column is necessary - that would make the procedure more complicated
> (in the worst cases.)
>
> Alec
>
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