On Wed, Jul 7, 2010 at 1:49 PM, David Sanders <[email protected]> wrote:
> I now want to substitute eps=1, so I do
>
> a.subs(eps = 1)
>
> but the response is still 3*epsilon !
This is due to the way Python functions work. Basically, doing
a.subs(eps=1)
is the same as doing
a.subs(**{'eps': 1})
When you use keyword arguments, the function gets the string 'eps'
rather than the var eps. So, it tries to look for a variable named
'eps' which it doesn't find. When you pass in the dictionary
explicitly:
a.subs({eps: 1})
the key is the actual variable object rather than a string so it knows
to do the right thing.
--Mike
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